1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
|
# Copyright (C) 2001-2018 by the Free Software Foundation, Inc.
#
# This program is free software; you can redistribute it and/or
# modify it under the terms of the GNU General Public License
# as published by the Free Software Foundation; either version 2
# of the License, or (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301, USA.
"""Get the normal delivery recipients from a Sendmail style :include: file.
"""
import os
import errno
from Mailman import Errors
def process(mlist, msg, msgdata):
if msgdata.has_key('recips'):
return
filename = os.path.join(mlist.fullpath(), 'members.txt')
try:
fp = open(filename)
except IOError, e:
if e.errno <> errno.ENOENT:
raise
# If the file didn't exist, just set an empty recipients list
msgdata['recips'] = []
return
# Read all the lines out of the file, and strip them of the trailing nl
addrs = [line.strip() for line in fp.readlines()]
# If the sender is in that list, remove him
sender = msg.get_sender()
if mlist.isMember(sender):
try:
addrs.remove(mlist.getMemberCPAddress(sender))
except ValueError:
# Don't worry if the sender isn't in the list
pass
msgdata['recips'] = addrs
|
