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# Copyright (C) 2001,2002 by the Free Software Foundation, Inc.
#
# This program is free software; you can redistribute it and/or
# modify it under the terms of the GNU General Public License
# as published by the Free Software Foundation; either version 2
# of the License, or (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.
"""Get the normal delivery recipients from a Sendmail style :include: file.
"""
import os
import errno
from Mailman import Errors
def process(mlist, msg, msgdata):
if msgdata.has_key('recips'):
return
filename = os.path.join(mlist.fullpath(), 'members.txt')
try:
fp = open(filename)
except IOError, e:
if e.errno <> errno.ENOENT:
raise
# If the file didn't exist, just set an empty recipients list
msgdata['recips'] = []
return
# Read all the lines out of the file, and strip them of the trailing nl
addrs = [line.strip() for line in fp.readlines()]
# If the sender is in that list, remove him
sender = msg.get_sender()
if mlist.isMember(sender):
try:
addrs.remove(mlist.getMemberCPAddress(sender))
except ValueError:
# Don't worry if the sender isn't in the list
pass
msgdata['recips'] = addrs
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