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# Copyright (C) 1998,1999,2000,2001,2002 by the Free Software Foundation, Inc.
#
# This program is free software; you can redistribute it and/or
# modify it under the terms of the GNU General Public License
# as published by the Free Software Foundation; either version 2
# of the License, or (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with this program; if not, write to the Free Software
# Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.
"""Parse bounce messages generated by Postfix.
This also matches something called `Keftamail' which looks just like Postfix
bounces with the word Postfix scratched out and the word `Keftamail' written
in in crayon.
It also matches something claiming to be `The BNS Postfix program'.
/Everybody's/ gotta be different, huh?
"""
import re
from cStringIO import StringIO
def flatten(msg, leaves):
# give us all the leaf (non-multipart) subparts
if msg.is_multipart():
for part in msg.get_payload():
flatten(part, leaves)
else:
leaves.append(msg)
# are these heuristics correct or guaranteed?
pcre = re.compile(r'[ \t]*the\s*(bns)?\s*(postfix|keftamail)', re.IGNORECASE)
rcre = re.compile(r'failure reason:$', re.IGNORECASE)
acre = re.compile(r'<(?P<addr>[^>]*)>:')
def findaddr(msg):
addrs = []
body = StringIO(msg.get_payload())
# simple state machine
# 0 == nothing found
# 1 == salutation found
state = 0
while 1:
line = body.readline()
if not line:
break
# preserve leading whitespace
line = line.rstrip()
# yes use match to match at beginning of string
if state == 0 and (pcre.match(line) or rcre.match(line)):
state = 1
elif state == 1 and line:
mo = acre.search(line)
if mo:
addrs.append(mo.group('addr'))
# probably a continuation line
return addrs
def process(msg):
if msg.get_type() <> 'multipart/mixed':
return None
# We're looking for the plain/text subpart with a Content-Description: of
# `notification'.
leaves = []
flatten(msg, leaves)
for subpart in leaves:
if subpart.get_type() == 'text/plain' and \
subpart.get('content-description', '').lower() == 'notification':
# then...
return findaddr(subpart)
return None
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