From af83ac5ec6c29be8b95513ad65dace6cecab617a Mon Sep 17 00:00:00 2001
From: Max Kellermann <max@duempel.org>
Date: Tue, 26 Aug 2008 08:27:12 +0200
Subject: mp3: dither a whole block at a time
Fill the whole output buffer at a time by using dither_buffer()'s
ability to decode blocks. Calculate how many samples fit into the
output buffer before each invocation.
---
src/inputPlugins/mp3_plugin.c | 12 +++++++++---
1 file changed, 9 insertions(+), 3 deletions(-)
(limited to 'src')
diff --git a/src/inputPlugins/mp3_plugin.c b/src/inputPlugins/mp3_plugin.c
index 2a6346bda..0a99cab21 100644
--- a/src/inputPlugins/mp3_plugin.c
+++ b/src/inputPlugins/mp3_plugin.c
@@ -932,12 +932,18 @@ static int mp3Read(mp3DecodeData * data, struct decoder *decoder,
pcm_length -= data->dropSamplesAtEnd;
}
- for (; i < pcm_length; i++) {
- unsigned int num_samples;
+ while (i < pcm_length) {
+ unsigned int num_samples =
+ (data->outputBufferEnd - data->outputPtr) /
+ (2 * MAD_NCHANNELS(&(data->frame).header));
+ if (num_samples > pcm_length - i)
+ num_samples = pcm_length - i;
+
+ i += num_samples;
num_samples = dither_buffer((mpd_sint16 *) data->outputPtr,
&data->synth, &data->dither,
- i, i + 1,
+ i - num_samples, i,
MAD_NCHANNELS(&(data->frame).header));
data->outputPtr += 2 * num_samples;
--
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